The Current Through A $50 - \Omega$ Resistor Is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$

Multiple Choice

The current through a $50 - \Omega$ resistor is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$ , where $t$ is measured in seconds. What is the rms current?

A) $1.6 \mathrm {~A}$
B) $0.80 \mathrm {~A}$
C) $1.1 \mathrm {~A}$
D) $0.57 \mathrm {~A}$