As shown in the figure, a wire and a

10 - \Omega

resistor are used to form a circuit in the shape of a square with dimensions

20 \mathrm {~cm}

20 \mathrm {~cm}

. A uniform but non-steady magnetic field is directed into the plane of the circuit. The magnitude of the magnetic field is steadily decreased from

2.70 \mathrm {~T}

0.90 \mathrm {~T}

in a time interval of

96 \mathrm {~ms}

. What is the induced current in the circuit, and what is its direction through the resistor?
$As shown in the figure, a wire and a 10 - \Omega resistor are used to form a circuit in the shape of a square with dimensions 20 \mathrm {~cm} by 20 \mathrm {~cm} . A uniform but non-steady magnetic field is directed into the plane of the circuit. The magnitude of the magnetic field is steadily decreased from 2.70 \mathrm {~T} to 0.90 \mathrm {~T} in a time interval of 96 \mathrm {~ms} . What is the induced current in the circuit, and what is its direction through the resistor? A) 75 \mathrm {~mA} , from b to a B) 45 \mathrm {~mA} , from b to a C) 45 \mathrm {~mA} , from a to b D) 110 \mathrm {~mA} , from a to b E) 75 \mathrm {~mA} , from a to b$
A)

75 \mathrm {~mA}

, from

b

a

45 \mathrm {~mA}

, from

b

a

45 \mathrm {~mA}

, from

a

b

110 \mathrm {~mA}

, from

a

b

75 \mathrm {~mA}

, from

a

b

The Current Through A 50−Ω50 - \Omega50−Ω Resistor Is I=(0.80 A)sin⁡(240t)I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )I=(0.80 A)sin(240t)

Multiple Choice

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The Current Through A $50 - \Omega$ Resistor Is $I = ( 0.80 \mathrm {~A} ) \sin ( 240 t )$

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