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A Proton That Is Initially at Rest Is Accelerated Through 500 V500 \mathrm {~V}

Question 104

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A proton that is initially at rest is accelerated through an electric potential difference of magnitude 500 V500 \mathrm {~V} . How much kinetic energy does it gain? (e=1.60×1019C) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)


A) 8.0×1017 J8.0 \times 10 ^ { - 17 } \mathrm {~J}
B) 500 J500 \mathrm {~J}
C) 1.6×1019 J1.6 \times 10 ^ { - 19 } \mathrm {~J}
D) 800 J800 \mathrm {~J}

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