After a Proton with an Initial Speed Of $1.50 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$

Multiple Choice

After a proton with an initial speed of $1.50 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$ has increased its speed by accelerating through a potential difference of $0.100 \mathrm { kV }$ , what is its final speed? $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {proton } } = \right.$ $1.67 \times 10 ^ { - 27 } \mathrm {~kg}$ )

A) $1.55 \times 10^6 \mathrm {~m} / \mathrm { s }$
B) $2.04 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$
C) $8.80 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$
D) $4.56 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$
E) $3.55 \times 10 ^ { 5 } \mathrm {~m} / \mathrm { s }$