How Much Work Is Needed to Carry an Electron from the Positive

Multiple Choice

How much work is needed to carry an electron from the positive terminal to the negative terminal of a $9.0 - \mathrm { V }$ battery. $\left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } , m _ { \text {electron } } = 9.11 \times 10 ^ { - 31 } \mathrm {~kg} \right)$

A) $14.4 \times 10 ^ { - 19 } \mathrm {~J}$
B) $9.0 \mathrm {~J}$
C) $1.6 \times 10 ^ { - 19 } \mathrm {~J}$
D) $17 \times 10 ^ { - 19 } \mathrm {~J}$
E) $14.4 \times 10 ^ { - 19 } \mathrm {~J} / \mathrm { C }$