The Potential Difference Between Two Square Parallel Plates Is $4.00 \mathrm {~V}$

Short Answer

The potential difference between two square parallel plates is $4.00 \mathrm {~V}$ . If the plate separation is $6.00 \mathrm {~cm}$ and they each measure $1.5 \mathrm {~m}$ by $1.5 \mathrm {~m}$ , what is the magnitude of the electric field between the plates?