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A Proton Moves 0.10 m0.10 \mathrm {~m} Along the Direction of an Electric Field of Magnitude

Question 96

Multiple Choice

A proton moves 0.10 m0.10 \mathrm {~m} along the direction of an electric field of magnitude 3.0 V/m3.0 \mathrm {~V} / \mathrm { m } . What is the change in kinetic energy of the proton? (e=1.60×1019C) \left( e = 1.60 \times 10 ^ { - 19 } \mathrm { C } \right)


A) 3.2×1020 J3.2 \times 10 ^ { - 20 } \mathrm {~J}
B) 1.6×1020 J1.6 \times 10 ^ { - 20 } \mathrm {~J}
C) 8.0×1021 J8.0 \times 10 ^ { - 21 } \mathrm {~J}
D) 4.8×1020 J4.8 \times 10 ^ { - 20 } \mathrm {~J}

Correct Answer:

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