How Many Grams of Ice At $- 17 ^ { \circ } \mathrm { C }$

Short Answer

How many grams of ice at $- 17 ^ { \circ } \mathrm { C }$ must be added to 741 grams of water that is initially at a temperature of $70 ^ { \circ } \mathrm { C }$ to produce water at a final temperature of $12 ^ { \circ } \mathrm { C } \text { ? }$ Assume that no heat is lost to the surroundings and that the container has negligible mass. The specific heat of liquid water is $4190 \mathrm {~J} / \mathrm { kg } \cdot \mathrm { C } ^ { \circ }$ and of ice is $2000 \mathrm {~J} / \mathrm { kg } \cdot \mathrm { C } ^ { \circ }$ For water the normal melting
point is $0 ^ { \circ } \mathrm { C }$ and the heat of fusion is $334 \times 10 ^ { 3 } \mathrm {~J} / \mathrm { kg }$ The normal boiling point is $100 ^ { \circ } \mathrm { C }$ and the heat of vaporization is $2.256 \times 10 ^ { 6 } \mathrm {~J} / \mathrm { kg }$