A Hollow Steel Ball of Diameter 3$\left( \rho \mathrm { Fe } = 7.87 \mathrm {~g} / \mathrm { cm } ^ { 3 } , \rho _ { \text {water } } = 1.00 \mathrm {~g} / \mathrm { cm } ^ { 3 } \right)$

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A Hollow Steel Ball of Diameter  3$\left( \rho \mathrm { Fe } = 7.87 \mathrm {~g} / \mathrm { cm } ^ { 3 } , \rho _ { \text {water } } = 1.00 \mathrm {~g} / \mathrm { cm } ^ { 3 } \right)$

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The Answer of A Hollow Steel Ball of Diameter  3$\left( \rho \mathrm { Fe } = 7.87 \mathrm {~g} / \mathrm { cm } ^ { 3 } , \rho _ { \text {water } } = 1.00 \mathrm {~g} / \mathrm { cm } ^ { 3 } \right)$

A Hollow Steel Ball of Diameter 3 A) 66 Cm
B) 131 Cm
C) 37 Cm

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A Hollow Steel Ball of Diameter 3 A) 66 Cm B) 131 Cm C) 37 Cm

Multiple Choice

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A Hollow Steel Ball of Diameter 3 A) 66 Cm
B) 131 Cm
C) 37 Cm

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge