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Solve the Problem μ= minimum + maximum 2 and σ= range 12\mu = \frac { \text { minimum } + \text { maximum } } { 2 } \text { and } \sigma = \frac { \text { range } } { \sqrt { 12 } }

Question 4

Multiple Choice

Solve the problem.
-In a continuous uniform distribution, μ= minimum + maximum 2 and σ= range 12\mu = \frac { \text { minimum } + \text { maximum } } { 2 } \text { and } \sigma = \frac { \text { range } } { \sqrt { 12 } }
Find the mean and standard deviation for a uniform distribution having a minimum of 2- 2 and a maximum of 6


A) μ=4,σ=2.31\mu = 4 , \sigma = 2.31
B) μ=2,σ=1.15\mu = 2 , \sigma = 1.15
C) μ=2,σ=2.31\mu = 2 , \sigma = 2.31

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