Solved

Solve the Equation for Solutions in the Interval [0, 2 [0,2π)[ 0,2 \pi )

Question 105

Multiple Choice

Solve the equation for solutions in the interval [0, 2 [0,2π) [ 0,2 \pi )
- cos2x=2cos2x\cos 2 x = \sqrt { 2 } - \cos 2 x


A) \varnothing
B) {π8,9π8,7π8,15π8}\left\{ \frac { \pi } { 8 } , \frac { 9 \pi } { 8 } , \frac { 7 \pi } { 8 } , \frac { 15 \pi } { 8 } \right\}
C) {π4,3π4,5π4,7π4}\left\{ \frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 } \right\}
D) {0,2π3,π,4π3}\left\{ 0 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } \right\}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions