Solved

Solve the Equation for Solutions in the Interval [0, 2 [0,2π)[ 0,2 \pi ) \text {. }

Question 17

Multiple Choice

Solve the equation for solutions in the interval [0, 2 [0,2π) [ 0,2 \pi ) \text {. }
- sin4x=32\sin 4 x = \frac { \sqrt { 3 } } { 2 }


A) {π4,5π4}\left\{ \frac { \pi } { 4 } , \frac { 5 \pi } { 4 } \right\}
B) {π12,π6,2π3,7π12,7π6,13π12,5π3,19π12}\left\{ \frac { \pi } { 12 } , \frac { \pi } { 6 } , \frac { 2 \pi } { 3 } , \frac { 7 \pi } { 12 } , \frac { 7 \pi } { 6 } , \frac { 13 \pi } { 12 } , \frac { 5 \pi } { 3 } , \frac { 19 \pi } { 12 } \right\}
C) {0,π4,π}\left\{ 0 , \frac { \pi } { 4 } , \pi \right\}
D) {0}\{ 0 \}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions