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Solve the Equation in the Interval [0°, 360°) sin2θ=sinθ\sin 2 \theta = - \sin \theta

Question 35

Multiple Choice

Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- sin2θ=sinθ\sin 2 \theta = - \sin \theta


A) {0,120,180,240}\left\{ 0 ^ { \circ } , 120 ^ { \circ } , 180 ^ { \circ } , 240 ^ { \circ } \right\}
B) {0,180}\left\{ 0 ^ { \circ } , 180 ^ { \circ } \right\}
C) {0,60,120,180,240,300}\left\{ 0 ^ { \circ } , 60 ^ { \circ } , 120 ^ { \circ } , 180 ^ { \circ } , 240 ^ { \circ } , 300 ^ { \circ } \right\}
D) {60,120,240,300}\left\{ 60 ^ { \circ } , 120 ^ { \circ } , 240 ^ { \circ } , 300 ^ { \circ } \right\}

Correct Answer:

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