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Solve the Equation in the Interval [0°, 360°) 3sin2θsinθ4=03 \sin ^ { 2 } \theta - \sin \theta - 4 = 0

Question 142

Multiple Choice

Solve the equation in the interval [0°, 360°) . Give solutions to the nearest tenth, if necessary.
- 3sin2θsinθ4=03 \sin ^ { 2 } \theta - \sin \theta - 4 = 0


A) {0}\left\{ 0 ^ { \circ } \right\}
B) {270}\left\{ 270 ^ { \circ } \right\}
C) {180}\left\{ 180 ^ { \circ } \right\}
D) {90}\left\{ 90 ^ { \circ } \right\}

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