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Solve the Equation for Exact Solutions Over the Interval [0 [0,2π)[ 0,2 \pi )

Question 48

Multiple Choice

Solve the equation for exact solutions over the interval [0, 2 [0,2π) [ 0,2 \pi )
- 2sin2x=sinx2 \sin ^ { 2 } x = \sin x


A) {0,π,π6,5π6}\left\{ 0 , \pi , \frac { \pi } { 6 } , \frac { 5 \pi } { 6 } \right\}
B) {π2,3π2,π3,2π3}\left\{ \frac { \pi } { 2 } , \frac { 3 \pi } { 2 } , \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } \right\}
C) {π3,2π3}\left\{ \frac { \pi } { 3 } , \frac { 2 \pi } { 3 } \right\}
D) {π6,5π6}\left\{ \frac { \pi } { 6 } , \frac { 5 \pi } { 6 } \right\}

Correct Answer:

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