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Solve the Equation for Exact Solutions Over the Interval [0 [0,2π)[ 0,2 \pi )

Question 178

Multiple Choice

Solve the equation for exact solutions over the interval [0, 2 [0,2π) [ 0,2 \pi )
- sec2x2=tan2x\sec ^ { 2 } x - 2 = \tan ^ { 2 } x


A) {π3}\left\{ \frac { \pi } { 3 } \right\}
B) {π4}\left\{ \frac { \pi } { 4 } \right\}
C) \varnothing
D) {π6}\left\{ \frac { \pi } { 6 } \right\}

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