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Solve the Equation for Solutions in the Interval [0, 2 [0,2π).[ 0,2 \pi ) .

Question 131

Multiple Choice

Solve the equation for solutions in the interval [0, 2 [0,2π) .[ 0,2 \pi ) .
- 2cos2x=1\sqrt { 2 } \cos 2 x = 1


A) {0,2π3,π,4π3}\left\{ 0 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } \right\}
B) {π8,9π8,7π8,15π8}\left\{ \frac { \pi } { 8 } , \frac { 9 \pi } { 8 } , \frac { 7 \pi } { 8 } , \frac { 15 \pi } { 8 } \right\}
C) \varnothing
D) {π4,3π4,5π4,7π4}\left\{ \frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 } \right\}

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