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Solve the Equation for Solutions in the Interval [0, 2 [0,2π).[ 0,2 \pi ) .

Question 93

Multiple Choice

Solve the equation for solutions in the interval [0, 2 [0,2π) .[ 0,2 \pi ) .
- sin22x=1\sin ^ { 2 } 2 x = 1


A) {π8,9π8}\left\{ \frac { \pi } { 8 } , \frac { 9 \pi } { 8 } \right\}
B) \varnothing
C) {0,2π3,π,4π3}\left\{ 0 , \frac { 2 \pi } { 3 } , \pi , \frac { 4 \pi } { 3 } \right\}
D) {π4,3π4,5π4,7π4}\left\{ \frac { \pi } { 4 } , \frac { 3 \pi } { 4 } , \frac { 5 \pi } { 4 } , \frac { 7 \pi } { 4 } \right\}

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