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Solve the Equation for Exact Solutions cot⁡(2θ)=csc⁡2θ−22cot⁡θ\cot ( 2 \theta ) = \frac { \csc ^ { 2 } \theta - 2 } { 2 \cot \theta }

Question 271

Essay

Solve the equation for exact solutions.
- cot⁡(2θ)=csc⁡2θ−22cot⁡θ\cot ( 2 \theta ) = \frac { \csc ^ { 2 } \theta - 2 } { 2 \cot \theta }

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