Solve the Problem $= 2 \pi \sqrt { 3.55555556 } \mathrm { sec }$

Multiple Choice

Solve the problem.
-Determine the period and frequency of oscillation when a pendulum of length 9 feet is released after being displaced 2 radians. Round constants to 8 decimal places, if necessary.

A) Period $= 2 \pi \sqrt { 3.55555556 } \mathrm { sec }$ , frequency $= \frac { 1 } { 2 \pi } \sqrt { 0.28125 }$ cycles per sec
B) Period $= 9 \pi \mathrm { sec }$ , frequency $= \frac { 1 } { 9 \pi }$ cycles per sec
C) Period $= \frac { \pi } { 9 }$ sec, frequency $= \frac { 9 } { \pi }$ cycles per sec
D) Period $= 2 \pi \sqrt { 0.28125 }$ sec, frequency $= \frac { 1 } { 2 \pi } \sqrt { 3.55555556 }$ cycles per sec