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Solve the Problem θ\theta To the Horizontal with an Initial Speed vOv _ { O }

Question 117

Multiple Choice

Solve the problem.
-The path of a projectile fired at an inclination θ\theta to the horizontal with an initial speed vOv _ { O } is a parabola. The range R\mathrm { R } of the projectile, the horizontal distance that the projectile travels, is found by the formula R=vO2sin2θg\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } where g=32.2\mathrm { g } = 32.2 feet per second per second or g=9.8\mathrm { g } = 9.8 meters per second per second. Find the range of a projectile fired with an initial velocity of 140 feet per second at an angle of 2727 ^ { \circ } to the horizontal. Round your answer to two decimal places.


A) 276.34ft276.34 \mathrm { ft }
B) 492.35ft492.35 \mathrm { ft }
C) 492.45ft492.45 \mathrm { ft }
D) 552.68ft552.68 \mathrm { ft }

Correct Answer:

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