Solved

Find the Exact Value of S in the Given Interval [3π2,2π];tans=33\left[ \frac { 3 \pi } { 2 } , 2 \pi \right] ; \tan \mathrm { s } = - \frac { \sqrt { 3 } } { 3 }

Question 130

Multiple Choice

Find the exact value of s in the given interval that has the given circular function value.
- [3π2,2π];tans=33\left[ \frac { 3 \pi } { 2 } , 2 \pi \right] ; \tan \mathrm { s } = - \frac { \sqrt { 3 } } { 3 }


A) s=π6s = \frac { \pi } { 6 }
B) s=7π4s = \frac { 7 \pi } { 4 }
C) s=11π6s = \frac { 11 \pi } { 6 }
D) s=5π3s = \frac { 5 \pi } { 3 }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions