Solve the Problem $\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$

Multiple Choice

Solve the problem.
-Snell's Law states that $\frac { c _ { 1 } } { c _ { 2 } } = \frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } }$ . Use this law to find the requested value. If $c _ { 1 } = 6 \times 10 ^ { 8 }$ , $c _ { 2 } = 4.66 \times 10 ^ { 8 } , \theta _ { 1 } = 43 ^ { \circ }$ , find $\theta _ { 2 }$ . Round your answer to the nearest degree.

A) $\theta _ { 2 } = 31 ^ { \circ }$
B) $\theta _ { 2 } = 34 ^ { \circ }$
C) $\theta _ { 2 } = 32 ^ { \circ }$
D) $\theta _ { 2 } = 35 ^ { \circ }$