Use the Given Values Of $n = 2112 , p = \frac { 3 } { 4 }$

Multiple Choice

Use the given values of $n = 2112 , p = \frac { 3 } { 4 }$ to find the minimum value that is not significantly low, $\mu - 2 \sigma$ , and the maximum value that is not significantly high, $\mu + 2 \sigma$ . Round your answer to the nearest hundredth unless otherwise noted.

A) Minimum: 1478.7; maximum: 1689.3
B) Minimum: 1544.2; maximum: 1623.8
C) Minimum: 1564.1; maximum: 1603.9
D) Minimum: 1623.8; maximum: 1544.2