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Its More Difficult to Start Moving a Heavy Carton from Rest

Question 41

Multiple Choice

Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because


A) The normal force is greater when the carton is at rest.
B) Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . <
Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . .
C) Initially, the normal force is not perpendicular to the applied force.
D) Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . <
Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . .
E) Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . =
Its more difficult to start moving a heavy carton from rest than it is to keep pushing it with constant velocity, because A) The normal force is greater when the carton is at rest. B)    <   . C) Initially, the normal force is not perpendicular to the applied force. D)    <   . E)    =   . .

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