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Solve the Problem V=392.0in.3\mathrm { V } = 392.0 \mathrm { in. } ^ { 3 }

Question 32

Multiple Choice

Solve the problem.
-The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. If V=392.0in.3\mathrm { V } = 392.0 \mathrm { in. } ^ { 3 } when T=420\mathrm { T } = 420 ^ { \circ } and P=15lb/in2\mathrm { P } = 15 \mathrm { lb } / \mathrm { in } ^ { 2 } what is the volume when T=200\mathrm { T } = 200 ^ { \circ } and P=15lb/in2?\mathrm { P } = 15 \mathrm { lb } / \operatorname { in } ^ { 2 } ?


A)  Solve the problem. -The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. If  \mathrm { V } = 392.0 \mathrm { in. } ^ { 3 }  when  \mathrm { T } = 420 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \mathrm { in } ^ { 2 }  what is the volume when  \mathrm { T } = 200 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \operatorname { in } ^ { 2 } ?  A)    B)    C)    D)
B)  Solve the problem. -The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. If  \mathrm { V } = 392.0 \mathrm { in. } ^ { 3 }  when  \mathrm { T } = 420 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \mathrm { in } ^ { 2 }  what is the volume when  \mathrm { T } = 200 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \operatorname { in } ^ { 2 } ?  A)    B)    C)    D)
C)  Solve the problem. -The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. If  \mathrm { V } = 392.0 \mathrm { in. } ^ { 3 }  when  \mathrm { T } = 420 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \mathrm { in } ^ { 2 }  what is the volume when  \mathrm { T } = 200 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \operatorname { in } ^ { 2 } ?  A)    B)    C)    D)
D)  Solve the problem. -The volume V of a given mass of gas varies directly as the temperature T and inversely as the pressure P. If  \mathrm { V } = 392.0 \mathrm { in. } ^ { 3 }  when  \mathrm { T } = 420 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \mathrm { in } ^ { 2 }  what is the volume when  \mathrm { T } = 200 ^ { \circ }  and  \mathrm { P } = 15 \mathrm { lb } / \operatorname { in } ^ { 2 } ?  A)    B)    C)    D)

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