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Find the Equation of the Circle $( x - 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 }$

Question 81

Short Answer

Find the equation of the circle. Express the equation in standard form
- $Find the equation of the circle. Express the equation in standard form - A) ( x - 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 } B) ( x + 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 } C) ( x + 1 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 1 ^ { 2 } D) ( x - 1 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 1 ^ { 2 }$
A) $( x - 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 }$
B) $( x + 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 }$
C) $( x + 1 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 1 ^ { 2 }$
D) $( x - 1 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 1 ^ { 2 }$

Find the Equation of the Circle (x−1)2+(y+3)2=12( x - 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 }(x−1)2+(y+3)2=12

Short Answer

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Find the Equation of the Circle $( x - 1 ) ^ { 2 } + ( y + 3 ) ^ { 2 } = 1 ^ { 2 }$

Correct Answer:
Verified
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