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Find an Equation for the Circle (x−19)2+(y−3)2=9( x - 19 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 9

Question 153

Short Answer

Find an equation for the circle.
-Center (19, 3), tangent (touching at one point)to the x-axis
A) (x−19)2+(y−3)2=9( x - 19 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 9
B) (x−3)2+(y−19)2=361( x - 3 ) ^ { 2 } + ( y - 19 ) ^ { 2 } = 361
C) (x−19)2+(y−3)2=361( x - 19 ) ^ { 2 } + ( y - 3 ) ^ { 2 } = 361
D) (x−3)2+(y−19)2=3( x - 3 ) ^ { 2 } + ( y - 19 ) ^ { 2 } = 3

Correct Answer:

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