Solved

Provide an Appropriate Response α=0.05\alpha = 0.05 Level of Significance to Support the Hypothesis That Cassie's Walk

Question 3

Multiple Choice

Provide an appropriate response.
-Wanting to enjoy the beautiful weather, Cassie took a walk with no destination in mind. At each four-way intersection, she randomly decided to head either north or east. A summary of her walk is shown below.
 Provide an appropriate response. -Wanting to enjoy the beautiful weather, Cassie took a walk with no destination in mind. At each four-way intersection, she randomly decided to head either north or east. A summary of her walk is shown below.    Is there evidence at the  \alpha = 0.05  level of significance to support the hypothesis that Cassie's walk was not random? A)   z = - 0.26  Since  | \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject  \mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random. B)   z = - 0.91  Since  | \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject  \mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random. C)   z = - 5.43  Since  | \mathrm { z } | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject  \mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random. D)   z = - 3.50  Since  | z | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject  \mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.

Is there evidence at the α=0.05\alpha = 0.05 level of significance to support the hypothesis that Cassie's walk was not random?


A) z=0.26z = - 0.26
Since z<z0.025=1.96| \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject H0\mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random.
B) z=0.91z = - 0.91
Since z<z0.025=1.96| \mathrm { z } | < \mathrm { z } _ { 0 } .025 = 1.96 , we do not reject H0\mathrm { H } _ { 0 } . There is not sufficient evidence to support the hypothesis that her walk was not random.
C) z=5.43z = - 5.43
Since z>z0.025=1.96| \mathrm { z } | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject H0\mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.
D) z=3.50z = - 3.50
Since z>z0.025=1.96| z | > \mathrm { z } _ { 0 } .025 = 1.96 , we reject H0\mathrm { H } _ { 0 } . There is sufficient evidence to support the hypothesis that her walk was not random.

Correct Answer:

verifed

Verified

Related Questions