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Solve the Problem A=12bhA = \frac { 1 } { 2 } b h

Question 3

Multiple Choice

Solve the problem.
-If the formula for the area of a triangle, A=12bhA = \frac { 1 } { 2 } b h , is solved for hh , then h=2Abh = \frac { 2 A } { b } . Use this formula to find hh if area A is 2y+18\frac { 2 y + 1 } { 8 } square feet and base bb is 3y511\frac { 3 y - 5 } { 11 } feet. Write hh in simplified form.


A) 4(3y5) 11(2y+1) ft\frac { 4 ( 3 y - 5 ) } { 11 ( 2 y + 1 ) } \mathrm { ft }
B) (2y+1) (3y5) 44ft\frac { ( 2 \mathrm { y } + 1 ) ( 3 \mathrm { y } - 5 ) } { 44 } \mathrm { ft }
C) 11(2y+1) 8(3y5) ft\frac { 11 ( 2 y + 1 ) } { 8 ( 3 y - 5 ) } \mathrm { ft }
D) 11(2y+1) 4(3y5) ft\frac { 11 ( 2 y + 1 ) } { 4 ( 3 y - 5 ) } \mathrm { ft }

Correct Answer:

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