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Solve the System {x+y+z=5xy+5z=34x+y+z=1\left\{ \begin{array} { l } x + y + z = 5 \\x - y + 5 z = 3 \\4 x + y + z = - 1\end{array} \right.

Question 16

Multiple Choice

Solve the system. If there is no solution or if the system's equations are dependent, so state.
- {x+y+z=5xy+5z=34x+y+z=1\left\{ \begin{array} { l } x + y + z = 5 \\x - y + 5 z = 3 \\4 x + y + z = - 1\end{array} \right.


A) infinitely many solutions; dependent equations
B) {(2,5,2) }\{ ( - 2,5,2 ) \}
C) no solution or \varnothing
D) {(2,5,2) }\{ ( 2,5 , - 2 ) \}

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