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Solve the Problem P(A)=0.22P ( A ) = 0.22 And P(B)=0.36P ( B ) = 0.36

Question 144

Multiple Choice

Solve the problem.
-Suppose that P(A) =0.22P ( A ) = 0.22 and P(B) =0.36P ( B ) = 0.36 , find P(AB) P ( A \cup B ) if AA and BB are mutually exclusive.


A) 0.07920.0792
B) 0
C) 0.50080.5008
D) 0.580.58

Correct Answer:

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