Solved

Determine the Possible Number of Positive Real Zeros and Negative f(x)=x51.5x418.39x3+3x2+47.51x10.849f ( x ) = x ^ { 5 } - 1.5 x ^ { 4 } - 18.39 x ^ { 3 } + 3 x ^ { 2 } + 47.51 x - 10.849

Question 125

Multiple Choice

Determine the possible number of positive real zeros and negative real zeros of the polynomial function using Descartes' rule of signs.
- f(x) =x51.5x418.39x3+3x2+47.51x10.849f ( x ) = x ^ { 5 } - 1.5 x ^ { 4 } - 18.39 x ^ { 3 } + 3 x ^ { 2 } + 47.51 x - 10.849


A) 3 or 1 positive zeros, 3 or 1 negative zeros
B) 2 or 0 positive zeros, 2 or 0 negative zeros
C) 2 or 0 positive zeros, 3 or 1 negative zeros
D) 3 or 1 positive zeros, 2 or 0 negative zeros

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions