Find the Real Solutions, If Any, of the Equation $\left\{\frac{-6-\sqrt{39}}{3}, \frac{-6+\sqrt{39}}{3}\right\}$

Multiple Choice

Find the real solutions, if any, of the equation. Use the quadratic formula.
-3x² + 12x + 1 = 0

A) $\left\{\frac{-6-\sqrt{39}}{3}, \frac{-6+\sqrt{39}}{3}\right\}$
B) $\left\{\frac{-6-\sqrt{33}}{6}, \frac{-6+\sqrt{33}}{6}\right\}$
C) $\left\{\frac{-6-\sqrt{33}}{3}, \frac{-6+\sqrt{33}}{3}\right\}$
D) $\left\{\frac{-12-\sqrt{33}}{3}, \frac{-12+\sqrt{33}}{3}\right\}$