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Solve the Following System of Quadratic Equations Algebraically by the Method

Question 24

Multiple Choice

Solve the following system of quadratic equations algebraically by the method of substitution.
{4x23y2+48=04x2y=0\left\{ \begin{array} { l } - 4 x ^ { 2 } - 3 y ^ { 2 } + 48 = 0 \\- 4 x - 2 y = 0\end{array} \right.


A) (3,23) ,(5,25) ( \sqrt { 3 } , - 2 \sqrt { 3 } ) , ( \sqrt { 5 } , - 2 \sqrt { 5 } )
B) (5,25) ,(5,25) ( - \sqrt { 5 } , 2 \sqrt { 5 } ) , ( \sqrt { 5 } , - 2 \sqrt { 5 } )
C) (5,25) ,(5,25) ( - \sqrt { 5 } , - 2 \sqrt { 5 } ) , ( \sqrt { 5 } , - 2 \sqrt { 5 } )
D) (3,23) ,(3,23) ( - \sqrt { 3 } , - 2 \sqrt { 3 } ) , ( \sqrt { 3 } , 2 \sqrt { 3 } )
E) (3,23) ,(3,23) ( - \sqrt { 3 } , 2 \sqrt { 3 } ) , ( \sqrt { 3 } , - 2 \sqrt { 3 } )

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