Essay
The following is an outline of a proof that . Fill in the blanks.Given sets and , to prove that , we suppose
then we show that
. So suppose that
Then by definition of complement,
So by definition of union, it is not the case that ( is in or is in ). Consequently, is not in
is not in because of De Morgan's law of logic. In symbols, this says that and . So by definition of complement,
and
Thus, by definition of intersection,
[as was to be shown].
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