A Two-Sample $z$ -Test for Two Population Proportions Is to Be Performed Using

Multiple Choice

A two-sample $z$ -test for two population proportions is to be performed using the $P$ -value approach. The null hypothesis is $H _ { 0 } : p _ { 1 } = p _ { 2 }$ and the alternative is $H _ { A } : p _ { 1 } \neq p _ { 2 }$ . Use the given sample data to find the $p$ -value for the hypothesis test. Give an interpretation of the $p$ -value.
$$n _ { 1 } = 200 , x _ { 1 } = 11 , n _ { 2 } = 100 \text {, and } x _ { 2 } = 8$$

A) $P$ -value $= 0.402$ ; If there is no difference in the proportions, there is a $40.2 \%$ chance of seeing the exact observed difference by natural sampling variation.
B) $P$ -value $= 0.1011$ ; There is about a $10.11 \%$ chance that the two proportions are equal.
C) $P$ -value $= 0.0201$ ; There is about a $2.01 \%$ chance that the two proportions are equal
D) $P$ -value $= 0.402$ ; If there is no difference in the proportions, there is about a $40.2 \%$ chance of seeing the observed difference or larger by natural sampling variation.
E) $P$ -value $= 0.0201$ ; If there is no difference in the proportions, there is about a $2.01 \%$ chance of seeing the observed difference or larger by natural sampling variation.