Solve the Problem $123,124,134,234$ $\mathrm { P } ( 4,3 ) = 4$

Multiple Choice

Solve the problem.
-List all the ordered arrangements of 4 objects 1, 2, 3, and 4 choosing 3 at a time without repetition. What is P(4,3) ?

A) $123,124,134,234$
$\mathrm { P } ( 4,3 ) = 4$
B) $123,124,132,142,143,213,214,231,241,243,312,314,321,341,342,412,413,421,423,431$ $\mathrm { P } ( 4,3 ) = 20$
C) $111,112,113,114,121,122,123,124,131,132,133,134,141,142,143,144,211,212,213,214,221,222,223$ , $224,231,232,233,234,241,242,243,244,311,312,313,314,321,322,323,324,331,332,333,334,341,342$ , $343,344,411,412,413,414,421,422,423,424,431,432,433,434,441,442,443,444$ $\mathrm { P } ( 4,3 ) = 64$
D) $123,124,132,134,142,143,213,214,231,234,241,243,312,314,321,324,341,342,412,413,421,423,431$ , 432 $\mathrm { P } ( 4,3 ) = 24$