Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$

Short Answer

Suppose $g : \mathbf { R } \rightarrow \mathbf { R }$ where $g ( x ) = \left\lfloor \frac { x - 1 } { 2 } \right\rfloor$
(a) If S= $\{ x \mid 1 < x < 6 \}$ , find $g ( S)$
(b) If T=\{2\} , find $g ^ { - 1 } ( T )$