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The Solutions To an=3an1+18an2a _ { n } = - 3 a _ { n - 1 } + 18 a _ { n - 2 }

Question 59

Short Answer

The solutions to an=3an1+18an2a _ { n } = - 3 a _ { n - 1 } + 18 a _ { n - 2 } have the form an=c3n+d(6)na _ { n } = c \cdot 3 ^ { n } + d \cdot ( - 6 ) ^ { n } Which of the following are solutions to the given recurrence relation?
(a) an=3n+1+(6)na _ { n } = 3 ^ { n + 1 } + ( - 6 ) ^ { n }
(b) an=5(6)na _ { n } = 5 ( - 6 ) ^ { n }
(c) an=3c6da _ { n } = 3 c - 6 d
(d) an=3n2a _ { n } = 3 ^ { n - 2 }
(e) an=π(3n+(6)n)a _ { n } = \pi \left( 3 ^ { n } + ( - 6 ) ^ { n } \right)
(f) an=3na _ { n } = - 3 ^ { n }
(g) an=3n(1+(2)n)a _ { n } = 3 ^ { n } \left( 1 + ( - 2 ) ^ { n } \right)
(h) an=3n+6na _ { n } = 3 ^ { n } + 6 ^ { n }

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(a) Yes (b...

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