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Four Friends (Joe, Tom, Miah, and Brownie) Are Lost on a Tropical

Question 12

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Four friends (Joe, Tom, Miah, and Brownie) are lost on a tropical island. Luckily the friends find a stash of 75 coconuts. The coconuts will be apportioned based on the weight of each person (i.e. the heavier person is, the more he gets) . The table below shows the weight of each of the four friends.
Four friends (Joe, Tom, Miah, and Brownie)  are lost on a tropical island. Luckily the friends find a stash of 75 coconuts. The coconuts will be apportioned based on the weight of each person (i.e. the heavier person is, the more he gets) . The table below shows the weight of each of the four friends.   Use Jefferson's Method to apportion the 75 coconuts. A)  Joe: 22 ; Tom: 17 ; Miah: 16 ; Brownie: 20 B)  Joe:  21 ;  Tom:  18 ;  Miah:  16 ;  Brownie: 20 C)  Joe: 22 ; Tom: 17 ; Miah: 15 ; Brownie: 21 D)  Joe: 21 ; Tom: 18 ; Miah: 15 ; Brownie: 21 E)  None of the above
Use Jefferson's Method to apportion the 75 coconuts.


A) Joe: 22 ; Tom: 17 ; Miah: 16 ; Brownie: 20
B) Joe: 21 ; Tom: 18 ; Miah: 16 ; Brownie: 20
C) Joe: 22 ; Tom: 17 ; Miah: 15 ; Brownie: 21
D) Joe: 21 ; Tom: 18 ; Miah: 15 ; Brownie: 21
E) None of the above

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