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Solve the Initial Value Problem (x+3)dydx2(x2+3x)y=ex2x+3;x>3,y(0)=0( x + 3 ) \frac { d y } { d x } - 2 \left( x ^ { 2 } + 3 x \right) y = \frac { e ^ { x ^ { 2 } } } { x + 3 } ; x > - 3 , y ( 0 ) = 0

Question 85

Multiple Choice

Solve the initial value problem.
- (x+3) dydx2(x2+3x) y=ex2x+3;x>3,y(0) =0( x + 3 ) \frac { d y } { d x } - 2 \left( x ^ { 2 } + 3 x \right) y = \frac { e ^ { x ^ { 2 } } } { x + 3 } ; x > - 3 , y ( 0 ) = 0


A) y=ex2(x3x+9) ,x>3y = - e ^ {- x ^ { 2 } } \left( \frac { x } { 3 x + 9 } \right) , x > - 3
B) y=ex2(x3x+9) ,x>3y = e ^ { x ^ { 2 } } \left( \frac { x } { 3 x + 9 } \right) , x > - 3
C) y=ex2(x3x+9) ,x>3y = - e ^ { x 2 } \left( \frac { x } { 3 x + 9 } \right) , x > - 3
D) y=ex2(x3x+9) ,x>3y = e ^ { - x ^ { 2 } } \left( \frac { x } { 3 x + 9 } \right) , x > - 3

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