Identify Equilibrium Values and Determine Which Are Stable and Which $$\frac { \mathrm { dy } } { \mathrm { dx } } = ( \mathrm { y } + 5 ) ( \mathrm { y } + 4 )$$

Multiple Choice

Identify equilibrium values and determine which are stable and which are unstable.
- $$\frac { \mathrm { dy } } { \mathrm { dx } } = ( \mathrm { y } + 5 ) ( \mathrm { y } + 4 )$$

A) y = 4 is a stable equilibrium value and y = -5 is an unstable equilibrium.
B) y = -5 is a stable equilibrium value and y = 4 is an unstable equilibrium.
C) y = -4 is a stable equilibrium value and y = 5 is an unstable equilibrium.
D) y = 5 is a stable equilibrium value and y = 4 is an unstable equilibrium.