Solved

Identify Equilibrium Values and Determine Which Are Stable and Which dydx=y216\frac { \mathrm { dy } } { \mathrm { dx } } = \mathrm { y } ^ { 2 } - 16

Question 6

Multiple Choice

Identify equilibrium values and determine which are stable and which are unstable.
- dydx=y216\frac { \mathrm { dy } } { \mathrm { dx } } = \mathrm { y } ^ { 2 } - 16


A) y = 4 is a stable equilibrium value and y = -4 is an unstable equilibrium.
B) y = -4 and y = 5 are stable equilibrium values.
C) y = -4 is a stable equilibrium value and y = 4 is an unstable equilibrium.
D) There are no equilibrium values.

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions