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Find the Moment or Center of Mass of the Wire y=36x2y = \sqrt { 36 - x ^ { 2 } }

Question 244

Multiple Choice

Find the moment or center of mass of the wire, as indicated.
-Find the center of mass of a wire that lies along the semicircle y=36x2y = \sqrt { 36 - x ^ { 2 } } if the density of the wire is δ=\delta = cosθ| \cos \theta | .


A) xˉ=2,yˉ=2\bar { x } = 2 , \bar { y } = 2
B) xˉ=0,yˉ=3\bar { x } = 0 , \bar { y } = 3
C) xˉ=0,yˉ=2\bar { x } = 0 , \bar { y } = 2
D) xˉ=3,yˉ=3\bar { x } = 3 , \bar { y } = 3

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