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-Locate the Centroid of a Semicircular Region B) C) yˉ=V2π=(4/3)πa32πa2=23a\bar { y } = \frac { V } { 2 \pi } = \frac { ( 4 / 3 ) \pi a ^ { 3 } } { 2 \pi a ^ { 2 } } = \frac { 2 } { 3 } a

Question 90

Multiple Choice

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-Locate the centroid of a semicircular region.


A) yˉ=V2π=(4/3) πa22π(1/2) πa2=43a\bar { y } = \frac { V } { 2 \pi } = \frac { ( 4 / 3 ) \pi \mathrm { a } ^ { 2 } } { 2 \pi ( 1 / 2 ) \pi \mathrm { a } ^ { 2 } } = \frac { 4 } { 3 } \mathrm { a }
B) yˉ=V2π=πa22π(1/2) πa2=1πa\bar { y } = \frac { V } { 2 \pi } = \frac { \pi \mathrm { a } ^ { 2 } } { 2 \pi ( 1 / 2 ) \pi \mathrm { a } ^ { 2 } } = \frac { 1 } { \pi } \mathrm { a }
C) yˉ=V2π=(4/3) πa32πa2=23a\bar { y } = \frac { V } { 2 \pi } = \frac { ( 4 / 3 ) \pi a ^ { 3 } } { 2 \pi a ^ { 2 } } = \frac { 2 } { 3 } a
D) yˉ=V2π=(4/3) πa32π(1/2) πa2=43πa\bar { y } = \frac { V } { 2 \pi } = \frac { ( 4 / 3 ) \pi a ^ { 3 } } { 2 \pi ( 1 / 2 ) \pi a ^ { 2 } } = \frac { 4 } { 3 \pi } a

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