Find the Absolute Extreme Values of the Function on the Interval

Multiple Choice

Find the absolute extreme values of the function on the interval.
- $$f ( x ) = \tan x , - \frac { \pi } { 6 } \leq x \leq \frac { \pi } { 6 }$$

A) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { \pi } { 6 }$ and $- \frac { \pi } { 6 }$ ; absolute minimum does not exist
B) absolute maximum is $- \frac { \sqrt { 3 } } { 3 }$ at $x = \frac { \pi } { 6 }$ ; absolute minimum is $\frac { \sqrt { 3 } } { 3 }$ at $x = - \frac { \pi } { 6 }$
C) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { 2 \pi } { 18 }$ ; absolute minimum is $- \frac { \sqrt { 3 } } { 3 }$ at $x = - \frac { \pi } { 12 }$
D) absolute maximum is $\frac { \sqrt { 3 } } { 3 }$ at $x = \frac { \pi } { 6 }$ ; absolute minimum is $- \frac { \sqrt { 3 } } { 3 }$ at $x = - \frac { \pi } { 6 }$