Find a Value of C That Makes the Function Continuous$f ( x ) = \left\{ \begin{array} { c c }
\frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \
c , & x = - 3
\end{array} ; x = - 3 \right.$

Question

Find a Value of C That Makes the Function Continuous$f ( x ) = \left\{ \begin{array} { c c } 
\frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \
c , & x = - 3
\end{array} ; x = - 3 \right.$

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The Answer of Find a Value of C That Makes the Function Continuous$f ( x ) = \left\{ \begin{array} { c c } 
\frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \
c , & x = - 3
\end{array} ; x = - 3 \right.$

Find a Value of C That Makes the Function Continuous $f ( x ) = \left\{ \begin{array} { c c } \frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \\c , & x = - 3\end{array} ; x = - 3 \right.$

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Find a Value of C That Makes the Function Continuous f(x)={x+35∣x+3∣′x≠−3c,x=−3;x=−3f ( x ) = \left\{ \begin{array} { c c } \frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \\c , & x = - 3\end{array} ; x = - 3 \right.f(x)={5∣x+3∣′x+3​c,​x=−3x=−3​;x=−3

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Find a Value of C That Makes the Function Continuous $f ( x ) = \left\{ \begin{array} { c c } \frac { x + 3 } { 5 | x + 3 | ^ { \prime } } & x \neq - 3 \\c , & x = - 3\end{array} ; x = - 3 \right.$

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