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Solve the Initial Value Problem drdθ=π2cosπ2θ,r(0)=10\frac { d r } { d \theta } = - \frac { \pi } { 2 } \cos \frac { \pi } { 2 } \theta , r ( 0 ) = - 10

Question 311

Multiple Choice

Solve the initial value problem.
- drdθ=π2cosπ2θ,r(0) =10\frac { d r } { d \theta } = - \frac { \pi } { 2 } \cos \frac { \pi } { 2 } \theta , r ( 0 ) = - 10


A) r=sinπ2θ10r = \sin \frac { \pi } { 2 } \theta - 10
B) r=sinπ2θ10r = - \sin \frac { \pi } { 2 } \theta - 10
C) r=π2sinπ2θ10r = - \frac { \pi } { 2 } \sin \frac { \pi } { 2 } \theta - 10
D) r=cosπ2θ11r = \cos \frac { \pi } { 2 } \theta - 11

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