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Solve the Problem g=9.8 m/sec2g = 9.8 \mathrm {~m} / \mathrm { sec } ^ { 2 }

Question 200

Multiple Choice

Solve the problem.
-At about what velocity do you enter the water is you jump from a 15 meter cliff? (Use g=9.8 m/sec2g = 9.8 \mathrm {~m} / \mathrm { sec } ^ { 2 } .)


A) 17 m/sec17 \mathrm {~m} / \mathrm { sec }
B) 2 m/sec2 \mathrm {~m} / \mathrm { sec }
C) 8.5 m/sec- 8.5 \mathrm {~m} / \mathrm { sec }
D) 17 m/sec- 17 \mathrm {~m} / \mathrm { sec }

Correct Answer:

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